Tentukan turunan fungsi In berikut ini : b). y=ln(x^(2)−3x+1)

Halo Roy H :) Jawaban: y' = [2x - 3] / [x^(2)−3x+1] perhatikan konsep turunan berikut: y = ln x => y' = 1/x y = ln (f(x)) => y' = [ f'(x) ][ 1/f(x) ] y = ax^b => y' = (b)(a)x^(b-1) sehingga turunan dari fungsi y=ln(x^(2)−3x+1) adalah... y = ln(x^(2)−3x+1) y' = [(2)x^(2-1) - (1)3x^(1-1) + 1(0)][ 1/(x^(2)−3x+1) ] y' = [2x^(1) - 3x^(0) + (0)][ 1/(x^(2)−3x+1) ] y' = [2x - 3][ 1/(x^(2)−3x+1) ] y' = [2x - 3] / [x^(2)−3x+1] Jadi, turunan dari y=ln(x^(2)−3x+1) adalah ... y' = [2x - 3] / [x^(2)−3x+1] Terima Kasih