DD
Dea D
14 Februari 2023 15:15
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DD
Dea D
14 Februari 2023 15:15
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NN
Neal N
14 Februari 2023 15:54
<p>,(,0=lim_(x→2) (x^(2)−6)/(2−sqrt(x+2)),),,(,2.Herisis,,),,(,(3^(2)−4)/(2=sqrt(112))=g/0(x),),,(,2.andwadnuner,),,(,((x−1)(x^(17)))/(1−sqrt(x+2))⋅(1+sqrt(x^(2)))/(2sqrt(x^(+2))),),,(,({(x+2)(x))(2+sqrt(xx)))/(4(x+2))=((x−2)(x+1)(2+sqrt(x+2)))/(−x+2)=((x−1)(x+c)(1+sqrt(x+2)))/(4−(x+3)=20),),,(,-4−a.,),,(,a=((x^(2)1)(2+sqrt(x+2)))/(−1)x=2],),,(,a=−ik,),</p>
,(,0=lim_(x→2) (x^(2)−6)/(2−sqrt(x+2)),),,(,2.Herisis,,),,(,(3^(2)−4)/(2=sqrt(112))=g/0(x),),,(,2.andwadnuner,),,(,((x−1)(x^(17)))/(1−sqrt(x+2))⋅(1+sqrt(x^(2)))/(2sqrt(x^(+2))),),,(,({(x+2)(x))(2+sqrt(xx)))/(4(x+2))=((x−2)(x+1)(2+sqrt(x+2)))/(−x+2)=((x−1)(x+c)(1+sqrt(x+2)))/(4−(x+3)=20),),,(,-4−a.,),,(,a=((x^(2)1)(2+sqrt(x+2)))/(−1)x=2],),,(,a=−ik,),
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