tentukan nilai sudut Tan 30° + cotan 60° / cosec 45° - sec 135°

Hai Jeny,kakak bantu jawab ya. Jawabannya adalah 1/2 √6. Konsep ✓ sec x = 1/cos x ✓ cotan x = 1/tan x ✓ cosec x = 1/sin x ✓ cos (180°-a) = -cos a >> tan 30°= 1/3 √3 >> cotan 60°=1/tan 60°= 1/√3 x √3/√3 = 1/3 √3 >> cosec 45° = 1/sin 45° = 1/(√2/2) = 2/√2 x √2/√2 = 2√2/2 = √2 >> cos 135° = cos (180°-45° = -cos 45°= -√2/2 sec 135°= 1/cos 135°= 1/(-√2/2) = -2/√2 x √2/√2 = -2√2/2 = -√2 Tan 30° + cotan 60° / cosec 45° - sec 135° =(1/3 √3 + 1/3 √3)/(√2-(-√2)) = (2/3 √3)/(2√2 x 3√2/3√2 = 2√6/6.2 = √6/2 = 1/2 √6 Jadi jawabannya adalah 1/2 √6. Semoga membantu.