tentukan hasil bagi dan sisa bagi dari (6x³-3x²+1)÷(2x²-3x+2) dengan menggunakan cara bersusun

<p>Jawaban: Hasil bagi = 3x + 3 dan sisa = 3x - 5</p><p>&nbsp;</p><p>Konsep:</p><p>Cara pembagian bersusun :</p><p>1. Bagi suku banyak dengan variabel tertinggi ke pembagi variabel tertinggi</p><p>2. Kalikan hasilnya dengan pembagi</p><p>3. Kurangi suku banyak dengan hasil kali pada langkah 2</p><p>4. Bagi kembali sisa suku banyak variabel tertinggi dengan pembagi variabel tertinggi</p><p>5. Langkah berlanjut sampai sisa suku banyak tidak dapat dibagi lagi oleh pembagi</p><p>&nbsp;</p><p>Pembahasan:</p><p>&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;<strong>3x + 3 &nbsp;→ Hasil Bagi</strong></p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;________________</p><p>2x² - 3x + 2 / &nbsp;6x³ - 3x² + 1</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 6x³ - 9x² + 6x</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; _________________-</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 6x² - 6x + 1</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 6x² - 9x + 6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; _________________-</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;<strong> 3x - 5 &nbsp;→ &nbsp;Sisa</strong></p><p>&nbsp;</p><p>Jadi, hasil bagi dan sisa bagi dari (6x³ - 3x² + 1) ÷ (2x² - 3x + 2) dengan menggunakan cara bersusun berturut-turut adalah 3x + 3 dan 3x - 5.</p>