Tentukan fog(2) bila f(x) = x'2 - x + 5 dan g(x) = 9 / x + 1

Halo, Kakak bantu jawab ya :) Jawaban : 11 Ingat, Fungsi Komposisi (fog)(x)=f(g(x)) Diketahui : f(x) = x^(2) - x + 5 dan g(x) = 9 / x + 1 (fog)(x) = f(g(x)) = f(9 / x + 1) = (9 / x + 1)^(2) - (9 / x + 1) + 5 = 81/((x+1)^(2)) - 9/(x+1) + 5 = 81/((x+1)^(2)) - 9(x+1)/((x+1)^(2)) + 5((x+1)^(2))/((x+1)^(2)) = 81-9(x+1)+5((x+1)^(2))/((x+1)^(2)) = 81-9x-9+5(x^(2)+2x+1)/((x+1)^(2)) = 81-9x-9+5x^(2)+10x+5)/((x+1)^(2)) = 5x^(2)+x+77/((x+1)^(2)) Hitung (fog)(2) = 5x^(2)+x+77/((x+1)^(2)) = 5(2)^(2)+2+77/((2+1)^(2)) = 20+2+77 / 3^(2) = 99/9 = 11 Jadi, nilai (fog)(2) adalah 11.