Tentukan akar akar dari persamaan kuadrat berikut dengan cara MELENGKAPKAN KUADRAT SEMPURNA b. x^(2)-4x+3=0

<p>Jawaban : 1 atau 3</p><p>&nbsp;</p><p>Ingat:</p><p>cara melengkapkan kuadrat sempurna:</p><p>&nbsp; &nbsp; &nbsp;x²+bx+c = 0</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;x²+bx = -c&nbsp;</p><p>(x + ½×b)² = -c + (½×b)²</p><p>&nbsp;</p><p>Pembahasan:</p><p>&nbsp; &nbsp; &nbsp; &nbsp;x² - 4x + 3 = 0</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; x²- 4x = -3&nbsp;</p><p>(x + ½×(-4))² = -3 + (½×(-4))²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; (x - 2)² = -3 + (-2)²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;(x - 2)² &nbsp;= -3 + 4</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;(x - 2)² &nbsp;= 1</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;x - 2 = ±√1</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;x - 2 = ±1</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;x - 2 = 1 &gt;&gt; x = 3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;atau</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;x - 2 = -1 &gt;&gt; x = 1</p><p>&nbsp;</p><p>Jadi, akar-akar persamaan kuadratnya adalah 1 atau 3.</p>