Sya bingung

<p><strong>&nbsp;</strong>²/_𝞪 + ²/_𝞫= <strong>-1 (A)</strong></p><p>&nbsp;</p><p><strong>Diketahui : </strong>x² + 4x + 8 = 0</p><p><strong>Ditanya : </strong>²/_𝞪 + ²/_𝞫</p><p><strong>Dijawab :</strong></p><p>²/_𝞪 + ²/_𝞫= ^{(2𝞫 + 2𝞪)}/_{(𝞪 . 𝞫)}</p><p>²/_𝞪 + ²/_𝞫= ^{(2(𝞫 + 𝞪))}/_{(𝞪 . 𝞫)&nbsp;}</p><p>&nbsp;</p><p>Mencari nilai 𝞪 + 𝞫 dan 𝞪 . 𝞫 :</p><p>→ x² + 4x + 8 = 0</p><p>ax² + bx + c = 0 maka a = 1, b = 4 dan c = 8</p><p>&nbsp;</p><p>→ x₁ = 𝞪 dan x₂ = 𝞫</p><p>𝞪 + 𝞫 = ^-b/_a</p><p>𝞪 + 𝞫 = ^-4/₁</p><p>𝞪 + 𝞫 = -4</p><p>&nbsp;</p><p>𝞪 . 𝞫 = ^c/_a</p><p>𝞪 . 𝞫 = ⁸/₁</p><p>𝞪 . 𝞫 = 8</p><p>&nbsp;</p><p>Subtitusi 𝞪 + 𝞫 = -4 dan 𝞪 . 𝞫 = 8 ke&nbsp;</p><p>²/_𝞪 + ²/_𝞫= ^{(2(𝞫 + 𝞪))}/_{(𝞪 . 𝞫)&nbsp;}</p><p>²/_𝞪 + ²/_𝞫= ^(2(-4))/₈</p><p>²/_𝞪 + ²/_𝞫= ^-8/₈</p><p>²/_𝞪 + ²/_𝞫= -1</p><p>&nbsp;</p><p>Selesai :D 🙏</p>