MA
M. Alfi
13 Juni 2024 16:41
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MA
M. Alfi
13 Juni 2024 16:41
Pertanyaan
Suatu sel volta terdiri dari elektroda Ag yang dicelupkan ke dalam larutan Ag+ 1 M, dan elektroda Zn yang dicelupkan ke dalam larutan Zn2+ 1 M. Bila diketahui: Ag+ + e- ---> Ag Eo = +0,80 volt Zn2+ + 2e- ---> Zn Eo = -0,76 volt Tentukan: reaksi selnya
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KL
Kevin L
Gold
08 Juli 2024 23:53
Langkah 1 Write down the half-reactions for the oxidation and reduction processes happening at each electrode: Ag+ + e- —> Ag (Eo = +0.80 V) Zn2+ + 2e- —> Zn (Eo = -0.76 V) Langkah 2 Identify the oxidation and reduction half-reactions: Ag+ is being reduced to Ag (reduction) Zn is being oxidized to Zn2+ (oxidation) Langkah 3 Write the overall cell reaction by combining the two half-reactions: Zn(s) + Ag+ (aq) —> Zn2+ (aq) + Ag(s) Langkah 4 Determine the cell potential (Ecell) by subtracting the reduction potential of the anode from the reduction potential of the cathode: Ecell = Ered(cathode) - Ered(anode) Ecell = (+0.80 V) - (-0.76 V) Ecell = 1.56 V Langkah 5 Write the notation for the voltaic cell using the anode and cathode reactions: Anode: Zn(s) | Zn2+ (1M) || Ag+ (1M) | Ag(s) : Cathode Jawaban Zn(s) | Zn2+ (1M) || Ag+ (1M) | Ag(s)
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