sin 37,5

Halo Jati, kakak bantu jawab ya. sin 37,5° = √[(4-(√6)+(√2))/4]. Konsep: sin (1/2)A = ±√[(1-cos A)/2] cos (A+B) = cos A cos B - sin A sin B Pembahasan: sin 37,5° = sin (1/2)(75°) = ±√[(1-cos 75°)/2] =±√[(1-(cos (45°+30°))/2] =±√[(1-(cos 45°cos 30°- sin 45°sin 30°))/2] =±√[(1-((1/2)(√2)(1/2)(√3)- (1/2)(√2)(1/2))/2] =±√[(1-((1/4)(√6)-(1/4)(√2))/2] =±√[(4-(√6)+(√2))/4] Karena sudut 37,5° berada di kuadran I maka nilai sin 37,5° bernilai positif. Jadi, sin 37,5° = √[(4-(√6)+(√2))/4]. Semoga membantu ya.