sebanyak 250 ml ch3cooh 0,256 dicampur drngan 250ml NaOH 0,256 jika Ka ch3cooh=1×10pangkat -5 maka ph larutan adalah?

Hai Marsa, jawaban yang benar adalah 9 + log 3,57. Langkah: mol CH₃COOH = V × M = 250 mL × 0,256 M = 64 mmol mol NaOH = V × M = 250 mL × 0,256 M = 64 mmol hitung konsentrasi dari garam dengan cara : reaksi : NaOH + CH₃COOH → CH₃COONa + H₂O mula-mula : 64 mmol 64 mmol bereaksi : 64 mmol 64 mmol 64 mmol 64 mmol ______________________________________________________ setimbang : - - 64 mmol 64 mmol M CH₃COONa = n/V = 64 mmol/ 500 mL = 0,128 M = 1,28 × 10⁻¹ M [OH⁻] = √Kw/Ka × [CH₃COO-] = √10⁻¹⁴/10⁻⁵ × 1,28 × 10⁻¹ = √1,28 × 10⁻¹⁰ = 3,57 × 10⁻⁵ pOH = - log [OH⁻] = - log 3,57 × 10⁻⁵ = 5 - log 3,57 pH = 14 - pOH = 14 - (5 - log 3,57) = 9 + log 3,57