Pak Diki mempunyai lahan berbentuk persegi panjang.Selisih antara panjang dan lebarnya adalah 5 meter. Jikaluas lahan tersebut adalah 50 m², lebar lahan adalah...

<p>Diketahui = Panjang &amp; lebar berselisih 5 meter&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Luas = 50 m²</p><p>Dit = lebar lahan&nbsp;</p><p>Jawaban&nbsp;</p><p>Panjang(p) &amp; lebar(l) berselisih 5 meter,maka&nbsp;</p><p><strong>p - l = 5 meter</strong></p><p>p = 5 + l&nbsp;</p><p>&nbsp;</p><p>Luas = p.l</p><p>50. &nbsp; &nbsp;= (5+l).l&nbsp;</p><p>50. &nbsp; &nbsp;= 5l + l²</p><p>l² + 5l - 50 = 0</p><p>I² + 5I - 10I - 50 = 0</p><p>I(I + 5) - 10(I + 5) = 0</p><p>(I - 10)(I + 5) = 0</p><p>I - 10 = 0. &nbsp; &nbsp; &nbsp; &nbsp;I + 5 = 0</p><p>I₁ = 10. &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;I₂ = -5(karena ukuran dalam suatu &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; benda hanya bernilai positif,maka&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;I₂= 5 meter)</p><p>&nbsp;</p><p>Maka ukuran lebar yang mungkin adalah 5 meter &amp; 10 meter</p><p>&nbsp;</p><p>&nbsp;</p><p>&nbsp;</p>