Roboguru
SD
SMP
SMA
UTBK/SNBT

Resha A

09 Juni 2022 10:51

Iklan

Resha A

09 Juni 2022 10:51

Pertanyaan

Pada percobaan melempar undi sekeping uang logam sebanyak tiga kali, tentukan sebaran peluang kejadian muncul gambar!

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

19

:

53

:

32

Klaim

1

2

Jawaban terverifikasi

Iklan

D. Yurmalia

27 September 2022 14:02

Jawaban terverifikasi

<p>Jawaban yang benar adalah x=0 maka P(x)=1/8, x=1 maka P(x)=3/8, x=2 maka P(x)=3/8, dan x=3 maka P(x)=1/8.</p><p>&nbsp;</p><p>Pertama, kita dapat menentukan banyaknya kejadian yang mungkin pada pelemparan 1 uang koin sebanyak 3 kali.</p><p>Pelemparan 1 &nbsp; &nbsp; &nbsp; Pelemparan 2 &nbsp; &nbsp; &nbsp; Pelemparan 3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>Sehingga dapat ditentukan sebaran peluang kejadian muncul gambar sebagai berikut.</p><p>1) Peluang muncul 1 gambar (3 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp; P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8</p><p>2) Peluang muncul 2 gambar (3 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp;P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8</p><p>3) Peluang muncul 3 gambar (1 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp;P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8</p><p>4) Peluang muncul 0 gambar (1 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp;P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8</p><p>Jadi, sebaran peluang kejadian muncul gambar adalah x = 0 → P(x) = 1/8 x = 1 → P(x) = 3/8 x = 2 → P(x) = 3/8 x = 3 → P(x) = 1/8.</p>

Jawaban yang benar adalah x=0 maka P(x)=1/8, x=1 maka P(x)=3/8, x=2 maka P(x)=3/8, dan x=3 maka P(x)=1/8.

 

Pertama, kita dapat menentukan banyaknya kejadian yang mungkin pada pelemparan 1 uang koin sebanyak 3 kali.

Pelemparan 1       Pelemparan 2       Pelemparan 3

             G                                 G                               G

             G                                 G                               A

             G                                 A                               G

             A                                 G                               G

             G                                 A                               A

             A                                 G                               A

             G                                 A                               A

             A                                 A                               A

Sehingga dapat ditentukan sebaran peluang kejadian muncul gambar sebagai berikut.

1) Peluang muncul 1 gambar (3 kemungkinan)

      P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8

2) Peluang muncul 2 gambar (3 kemungkinan)

     P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8

3) Peluang muncul 3 gambar (1 kemungkinan)

     P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8

4) Peluang muncul 0 gambar (1 kemungkinan)

     P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8

Jadi, sebaran peluang kejadian muncul gambar adalah x = 0 → P(x) = 1/8 x = 1 → P(x) = 3/8 x = 2 → P(x) = 3/8 x = 3 → P(x) = 1/8.

Iklan

D. Yurmalia

15 September 2022 09:29

<p>Jawaban yang benar dapat dilihat di bawah ini.</p><p>&nbsp;</p><p>Pertama, kita dapat menentukan banyaknya kejadian yang mungkin pada pelemparan 1 uang koin sebanyak 3 kali.</p><p>Pelemparan 1 &nbsp; &nbsp; &nbsp; Pelemparan 2 &nbsp; &nbsp; &nbsp; Pelemparan 3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>Sehingga dapat ditentukan sebaran peluang kejadian muncul gambar sebagai berikut.</p><p>1) Peluang muncul 1 gambar (3 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp; P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8</p><p>2) Peluang muncul 2 gambar (3 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp;P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8</p><p>3) Peluang muncul 3 gambar (1 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp;P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8</p>

Jawaban yang benar dapat dilihat di bawah ini.

 

Pertama, kita dapat menentukan banyaknya kejadian yang mungkin pada pelemparan 1 uang koin sebanyak 3 kali.

Pelemparan 1       Pelemparan 2       Pelemparan 3

             G                                 G                               G

             G                                 G                               A

             G                                 A                               G

             A                                 G                               G

             G                                 A                               A

             A                                 G                               A

             G                                 A                               A

Sehingga dapat ditentukan sebaran peluang kejadian muncul gambar sebagai berikut.

1) Peluang muncul 1 gambar (3 kemungkinan)

      P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8

2) Peluang muncul 2 gambar (3 kemungkinan)

     P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8

3) Peluang muncul 3 gambar (1 kemungkinan)

     P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8

Mau pemahaman lebih dalam untuk soal ini?

Tanya ke AiRIS

Yuk, cobain chat dan belajar bareng AiRIS, teman pintarmu!

Chat AiRIS

LATIHAN SOAL GRATIS!

Drill Soal

Latihan soal sesuai topik yang kamu mau untuk persiapan ujian

Cobain Drill Soal

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

Gold Icon

Klaim Gold gratis sekarang!

Dengan Gold kamu bisa tanya soal ke Forum sepuasnya, lho.

Pertanyaan serupa

Nilai dari |−7+4|=… A. 3 B. −3 C. 11 D. −4 E. 4

341

5.0

Jawaban terverifikasi

cos 105° - cos 15° adalah

87

5.0

Jawaban terverifikasi

Iklan

Titik P(p,−2) melalui fungsi kuadrat y=x²−5x+4, maka nilai p yang mungkin adalah .... A. 0 B. −1 C. −2 D. 3 E. 4

157

4.0

Jawaban terverifikasi

persamaan-persamaan berikut yang merupakan persamaan lingkaran adalah a.) x²+y²+4x-6y-12=0 b.) x²+y²+4x-6y-16=0 c.) x²-y²+4x-6y+16=0 d.) x²+y²+4x-6y+5xy-12=0 e.) x²+y²+4x-6y+13=0

192

3.0

Jawaban terverifikasi

Apa yang dimaksud dengan Statistika?

42

5.0

Jawaban terverifikasi