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09 Juni 2022 10:51

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Pada percobaan melempar undi sekeping uang logam sebanyak tiga kali, tentukan sebaran peluang kejadian muncul gambar!

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Jawaban terverifikasi

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D. Yurmalia

Master Teacher

27 September 2022 14:02

Jawaban terverifikasi

<p>Jawaban yang benar adalah x=0 maka P(x)=1/8, x=1 maka P(x)=3/8, x=2 maka P(x)=3/8, dan x=3 maka P(x)=1/8.</p><p>&nbsp;</p><p>Pertama, kita dapat menentukan banyaknya kejadian yang mungkin pada pelemparan 1 uang koin sebanyak 3 kali.</p><p>Pelemparan 1 &nbsp; &nbsp; &nbsp; Pelemparan 2 &nbsp; &nbsp; &nbsp; Pelemparan 3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>Sehingga dapat ditentukan sebaran peluang kejadian muncul gambar sebagai berikut.</p><p>1) Peluang muncul 1 gambar (3 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp; P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8</p><p>2) Peluang muncul 2 gambar (3 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp;P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8</p><p>3) Peluang muncul 3 gambar (1 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp;P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8</p><p>4) Peluang muncul 0 gambar (1 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp;P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8</p><p>Jadi, sebaran peluang kejadian muncul gambar adalah x = 0 → P(x) = 1/8 x = 1 → P(x) = 3/8 x = 2 → P(x) = 3/8 x = 3 → P(x) = 1/8.</p>

Jawaban yang benar adalah x=0 maka P(x)=1/8, x=1 maka P(x)=3/8, x=2 maka P(x)=3/8, dan x=3 maka P(x)=1/8.

 

Pertama, kita dapat menentukan banyaknya kejadian yang mungkin pada pelemparan 1 uang koin sebanyak 3 kali.

Pelemparan 1       Pelemparan 2       Pelemparan 3

             G                                 G                               G

             G                                 G                               A

             G                                 A                               G

             A                                 G                               G

             G                                 A                               A

             A                                 G                               A

             G                                 A                               A

             A                                 A                               A

Sehingga dapat ditentukan sebaran peluang kejadian muncul gambar sebagai berikut.

1) Peluang muncul 1 gambar (3 kemungkinan)

      P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8

2) Peluang muncul 2 gambar (3 kemungkinan)

     P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8

3) Peluang muncul 3 gambar (1 kemungkinan)

     P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8

4) Peluang muncul 0 gambar (1 kemungkinan)

     P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8

Jadi, sebaran peluang kejadian muncul gambar adalah x = 0 → P(x) = 1/8 x = 1 → P(x) = 3/8 x = 2 → P(x) = 3/8 x = 3 → P(x) = 1/8.


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D. Yurmalia

Master Teacher

15 September 2022 09:29

<p>Jawaban yang benar dapat dilihat di bawah ini.</p><p>&nbsp;</p><p>Pertama, kita dapat menentukan banyaknya kejadian yang mungkin pada pelemparan 1 uang koin sebanyak 3 kali.</p><p>Pelemparan 1 &nbsp; &nbsp; &nbsp; Pelemparan 2 &nbsp; &nbsp; &nbsp; Pelemparan 3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;G &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A</p><p>Sehingga dapat ditentukan sebaran peluang kejadian muncul gambar sebagai berikut.</p><p>1) Peluang muncul 1 gambar (3 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp; P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8</p><p>2) Peluang muncul 2 gambar (3 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp;P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8</p><p>3) Peluang muncul 3 gambar (1 kemungkinan)</p><p>&nbsp; &nbsp; &nbsp;P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8</p>

Jawaban yang benar dapat dilihat di bawah ini.

 

Pertama, kita dapat menentukan banyaknya kejadian yang mungkin pada pelemparan 1 uang koin sebanyak 3 kali.

Pelemparan 1       Pelemparan 2       Pelemparan 3

             G                                 G                               G

             G                                 G                               A

             G                                 A                               G

             A                                 G                               G

             G                                 A                               A

             A                                 G                               A

             G                                 A                               A

Sehingga dapat ditentukan sebaran peluang kejadian muncul gambar sebagai berikut.

1) Peluang muncul 1 gambar (3 kemungkinan)

      P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8

2) Peluang muncul 2 gambar (3 kemungkinan)

     P(A)=3.(1/2.1/2.1/2)=3.1/8=3/8

3) Peluang muncul 3 gambar (1 kemungkinan)

     P(A)=1.(1/2.1/2.1/2)=1.1/8=1/8


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