NAYLA N
22 November 2022 11:30
Iklan
NAYLA N
22 November 2022 11:30
Pertanyaan
Nilai sin π/3 + alpha + sin π/3 - alpha/cos π/2 + alpha) - cos π/2 - alpha)) untuk alpha = -π/6 adalah.... a.0 b. 1/2 C. 1/2√3 d. 3/2 e 2
Nilai sin π/3 + alpha + sin π/3 - alpha/cos π/2 + alpha) - cos π/2 - alpha)) untuk alpha = -π/6 adalah....
a.0
b. 1/2
C. 1/2√3
d. 3/2
e 2
1
2
Iklan
M. F
23 November 2022 03:45
<p>asumsikan soalnya adalah:</p><p>Nilai [sin (π/3 + α) + sin (π/3 - α)]/[cos (π/2 + α) - cos (π/2 - α)] untuk α = -π/6 adalah ...</p><p> </p><p>Ingat.</p><p>sin π/6 = sin 30° = ½</p><p>sin π/2 = sin 90° = 1</p><p>cos π/3 = cos 60° = ½</p><p>cos 2π/3 = cos 120° = -½</p><p> </p><p>Maka,</p><p>[sin (π/3 + α) + sin (π/3 - α)]/[cos (π/2 + α) - cos (π/2 - α)]</p><p>= [sin (π/3 + (-π/6)) + sin (π/3 - (-π/6))]/[cos (π/2 + (-π/6)) - cos (π/2 - (-π/6))]</p><p>= [sin (π/3 - π/6) + sin (π/3 + π/6)]/[cos (π/2 - π/6)) - cos (π/2 + π/6)]</p><p>= [sin π/6 + sin π/2]/[(cos π/3 - cos 2π/3]</p><p>= [½ + 1]/[(½ - (-½)]</p><p>= 3/2 : 1</p><p>= 3/2 </p><p> </p><p>Jadi, jawaban yang tepat adalah d. 3/2</p>
asumsikan soalnya adalah:
Nilai [sin (π/3 + α) + sin (π/3 - α)]/[cos (π/2 + α) - cos (π/2 - α)] untuk α = -π/6 adalah ...
Ingat.
sin π/6 = sin 30° = ½
sin π/2 = sin 90° = 1
cos π/3 = cos 60° = ½
cos 2π/3 = cos 120° = -½
Maka,
[sin (π/3 + α) + sin (π/3 - α)]/[cos (π/2 + α) - cos (π/2 - α)]
= [sin (π/3 + (-π/6)) + sin (π/3 - (-π/6))]/[cos (π/2 + (-π/6)) - cos (π/2 - (-π/6))]
= [sin (π/3 - π/6) + sin (π/3 + π/6)]/[cos (π/2 - π/6)) - cos (π/2 + π/6)]
= [sin π/6 + sin π/2]/[(cos π/3 - cos 2π/3]
= [½ + 1]/[(½ - (-½)]
= 3/2 : 1
= 3/2
Jadi, jawaban yang tepat adalah d. 3/2
· 0.0 (0)
Iklan
Fhiraza I
22 November 2022 13:14
<p>1⁄2 √3</p>
1⁄2 √3
· 5.0 (1)
Mau pemahaman lebih dalam untuk soal ini?
Tanya ke AiRIS
Yuk, cobain chat dan belajar bareng AiRIS, teman pintarmu!
LATIHAN SOAL GRATIS!
Drill Soal
Latihan soal sesuai topik yang kamu mau untuk persiapan ujian
Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!
