Nilai dari sin 600° + sec 660° − cos 690° = ...

Jawaban: 2 – √3 Konsep! sin (n·360° + a) = sin a sec (n·360° + a) = sec a cos (n·360° + a) = cos a sin (180° + a) = –sin a sec (270° + a) = csc a cos (360° – a) = cos a Pembahasan: sin 600° = sin (360° + 240°) = sin (1·360° + 240°) = sin 240° = sin (180° + 60°) = –sin 60° = –√3/2 sec 660° = sec (360° + 300°) = sec (1·360° + 300°) = sec 300° = sec (270° + 30°) = csc 30° = 2 cos 690° = cos (360° + 330°) = cos (1·360° + 330°) = cos 330° = cos (360° – 30°) = cos 30° = √3/2 Maka, sin 600° + sec 660° − cos 690° = –√3/2 + 2 – (√3/2) = 2 – ((2√3)/2) = 2 – √3 Jadi, nilai dari sin 600° + sec 660° − cos 690° = 2 – √3.