nilai cos(11/6π)⋅tan(−7/4π)−sin(−7/6π)⋅cot(11/6π)=sqrt(c). maka nilai dari c^(3)=…

Jawaban : 27 Ingat! cos ( 2π - a) = cos a tan (2π + a) = tan a sin (π + a) = - sin a cot a = 1/tan a tan (-a) = - tan a sin (-a) = - sin a Perhatikan perhitungan berikut cos (11/6π) = cos (2π-(1/6)π) = cos (1/6)π = ½√3 tan (-7/4π) = - tan (7/4π) = - tan (2π - 1/4π) = - (-tan (1/4)π) = tan (1/4)π = 1 sin(-7/6π) = - sin(7/6)π = - sin (π + π/6) = - (- sin π/6) = sin π/6 = ½ cot (11/6π) = 1/tan (11/6π) = 1/tan (2π - (1/6)π) = 1/(-tan (1/6)π) = 1/(-⅓√3) =-3/√3 = -√3 Sehingga cos(11/6π).tan (-7/4π) - sin (-7/6π).cot(11/6π) = √c ½√3. 1 - ½(-√3) = √c ½√3 + ½√3 = √c √3 = √c 3 = c Maka c³ = 3³ = 27 Dengan demikian nilai dari c³ = 27.