Mohon bantuannya teman teman

<p>diketahui y = x² + 6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; faktor skala = ¹/₃</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; titik pusat P(6,-3)</p><p>ditanya persamaan bayangan kurva...?</p><p>lesaian:</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;(x') = (¹/₃ &nbsp; &nbsp;0 &nbsp; )(x - 6) + ( 6 )</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;(y') &nbsp; &nbsp;( 0 &nbsp; &nbsp; &nbsp;¹/₃)(y + 3) &nbsp; &nbsp;(-3)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; x - 6 &nbsp; &nbsp; &nbsp; &nbsp; 18 &nbsp; &nbsp; &nbsp; &nbsp;x + 12</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; x' &nbsp;= ------- + &nbsp;----- = &nbsp; --------&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;3 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 3 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &lt;=&gt; 3x' = x + 12</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &lt;=&gt; x = 3x' - 12</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; y + 3 &nbsp; &nbsp; &nbsp; &nbsp;9 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; y - 6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; y' &nbsp;= ------- - &nbsp;----- = &nbsp; --------</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;3 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;3 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &lt;=&gt; 3y' = y - 6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &lt;=&gt; y = 3y' + 6</p><p>persamaan kurva y = x² + 6</p><p>persamaan bayangannya:</p><p>y = x² + 6</p><p>3y' + 6 = (3x' - 12)² + 6</p><p>3y' + 6 = 9x'² - 24x' + 2 + 6</p><p>3y' = 9x'² - 24x' + 2</p><p>3y = 9x² - 24x + 2</p><p>jadi persamaan bayangannya 3y = 9x² - 24x + 2</p><p>semoga membantu.</p>