Minta tolong ya kak.

<p>Jawabannya, besar arus yang mengalir adalah i₁ = i₂ = 6 A ; i₃ = 2 A ; i₄ = 4 A ; i₅ = 8/3 A ; i₆ = 4/3 A ; i₇ = 12 A</p><p>&nbsp;</p><p>Pembahasan :</p><p>Soal ini dapat diselesaikan dengan menggunakan hukum 1 kirchoff yaitu :&nbsp;</p><p>∑ arus masuk titik percabangan = ∑ arus keluar titik percabangan</p><p>&nbsp;</p><p>* i₁ = i₂ = i</p><p>&nbsp; ∑ i_masuk = ∑ i_keluar</p><p>&nbsp; &nbsp; &nbsp; &nbsp; 12 = i₁ + i₂</p><p>&nbsp; &nbsp; &nbsp; &nbsp; 12 = i + i</p><p>&nbsp; &nbsp; &nbsp; &nbsp; 12 = 2.i</p><p>&nbsp; &nbsp; &nbsp; &nbsp; i = 12/2 = 6 A</p><p>maka i₁ = i₂ = 6 A</p><p>&nbsp;</p><p>* i₃ : i₄ = 1 : 2 &nbsp; ---&gt; bisa diartikan i₃ = 1.x dan i₄ = 2.x</p><p>∑ i_masuk = ∑ i_keluar</p><p>&nbsp; &nbsp; &nbsp; &nbsp; i₂ = i₃ + i₄</p><p>&nbsp; &nbsp; &nbsp; &nbsp; 6 = 1.x + 2.x</p><p>&nbsp; &nbsp; &nbsp; &nbsp; 6 = 3.x</p><p>&nbsp; &nbsp; &nbsp; &nbsp; x = 6/3 = 2 A</p><p>sehingga :</p><p>i₃ = 1.x = 1. 2 = 2 A</p><p>i₄ = 2.x = 2.2 = 4 A</p><p>&nbsp;</p><p>* i₅ = 2.i₆</p><p>∑ i_masuk = ∑ i_keluar</p><p>&nbsp; &nbsp; &nbsp; &nbsp; i₄ = i₅ + i₆</p><p>&nbsp; &nbsp; &nbsp; &nbsp; 4 = 2.i₆ + i₆</p><p>&nbsp; &nbsp; &nbsp; &nbsp; 4 = 3.i₆</p><p>&nbsp; &nbsp; &nbsp; &nbsp; i₆ = 4/3 A</p><p>sehingga</p><p>i₅ = 2.i₆</p><p>i₅ = 2. (4/3)</p><p>i₅ = 8/3 A</p><p>&nbsp;</p><p>* Yang terakhir :</p><p>∑ i_masuk = ∑ i_keluar</p><p>i₁ + i₃ + i₅ + i₆ = i₇</p><p>atau</p><p>i₇ = i₁ + i₃ + i₅ + i₆</p><p>i₇ = 6 + 2 + 8/3 + 4/3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; i₇ = 12 &nbsp;A</p><p>&nbsp;</p><p>Jadi besar arus i₁sampai i₇ pada rangkaian adalah i₁ = i₂ = 6 A ; i₃ = 2 A ; i₄ = 4 A ; i₅ = 8/3 A ; i₆ = 4/3 A ; i₇ = 12 A</p>