Maka bayangan parabola tersebut adalah...

<p>sebuah parabola y = x² - x - 5 di translasi T(-1,2), berarti bayangannya;</p><p>x' = x - 1</p><p>y' = y + 2</p><p>kemudian didilatasi terhadap pusat O(0,0) dengan faktor 1/3, berarti bayangannya;</p><p>( x" ) = ( 1/3 &nbsp; &nbsp;0 &nbsp; &nbsp;)(x - 1)</p><p>( y" ) &nbsp; &nbsp;( &nbsp; 0 &nbsp; &nbsp; 1/3 )(y + 2)</p><p>&nbsp;x" = (x-1)/3 &lt;=&gt; 3x" = x-1</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&lt;=&gt; x = 3x" + 1</p><p>y" = (y+2)/3 &lt;=&gt; 3y" = y+2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&lt;=&gt; y = 3y"-2</p><p>substitusikan ke parabola;</p><p>y = x² - x - 5&nbsp;</p><p>3y" - 2 = (3x" + 1)² - (3x" + 1) - 5</p><p>3y" - 2 = 9x"² + 6x" + 1 - 3x" - 1 - 5</p><p>3y" - 2 = 9x"² + 3x" - 5</p><p>3y" = 9x"² + 3x" - 3</p><p>y" = 3x"² + x" - 1</p><p>y = 3x² + x - 1</p><p>pilihan jawabannya C</p><p>semoga membantu.</p>