Luas sebuah segitiga siku-siku ABC adalah 5,5 cm² jika panjang AB adalah 4 - akar 5, Tentukan panjang AC

<p>Dik:pada segitiga siku-siku&nbsp;</p><p>&nbsp; &nbsp; &nbsp; -luas segitiga 5,5cm²</p><p>&nbsp; &nbsp; &nbsp; -panjangAB=4-(√5)</p><p>Dit:panjang AC....?</p><p>Jawaban:Luas &nbsp; =1/2×alas×tinggi</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;5,5cm²=1/2×(4-√5)×AC</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;11cm² =(4-√5)cm×AC</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;AC &nbsp; &nbsp; &nbsp; =11cm²/(4-√5)cm</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;AC &nbsp; &nbsp; &nbsp;=(11cm²×(4-√5)cm)×((4+√5)/</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;(4+√5))</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;AC &nbsp; &nbsp; &nbsp;=(11cm²×(4+√5))/((4-√5)×</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; (4+√5))</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;AC &nbsp; &nbsp; &nbsp;=(44+11√5)cm²/(16-5)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;AC &nbsp; &nbsp; &nbsp;=(44+11√5)cm²/11</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;AC &nbsp; &nbsp; &nbsp;= 4+√5 cm</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;AC &nbsp; &nbsp; &nbsp;=4+2,236</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;AC &nbsp; &nbsp; &nbsp;=6,236cm</p>