Luthfi A
03 Desember 2023 06:44
Iklan
Luthfi A
03 Desember 2023 06:44
Pertanyaan
lengkapilah tabel stoikiometri yang ada pada gambar, dan jelaskan caranya
lengkapilah tabel stoikiometri yang ada pada gambar, dan jelaskan caranya
1
1
Iklan
Bakwan G
03 Desember 2023 11:19
<p><strong>•• H<sub>2</sub>SO<sub>4</sub></strong></p><p><strong>Diketahui </strong>: bilangan avogadro H<sub>2</sub>SO<sub>4 </sub>= 3,02 × 10²³</p><p><strong>Ditanya :</strong> mol, massa, molaritas, Mr, Volume</p><p><strong>Dijawab :</strong></p><ul><li>Mencari <strong>Mr H<sub>2</sub>SO<sub>4</sub> </strong></li></ul><p>Mr H<sub>2</sub>SO<sub>4</sub> = (Ar H × 2) + (Ar S × 1) + (Ar O × 4)</p><p>Mr H<sub>2</sub>SO<sub>4</sub> = (1 × 2) + (32 × 1) + (16 × 4)</p><p>Mr H<sub>2</sub>SO<sub>4</sub> = 2 + 32 + 64</p><p>Mr H<sub>2</sub>SO<sub>4</sub> = <strong>98 g/mol</strong></p><ul><li>Mencari<strong> mol H<sub>2</sub>SO<sub>4</sub></strong></li></ul><p>mol H<sub>2</sub>SO<sub>4 </sub>= <sup>(jumlah partikel H</sup><sub><sup>2</sup></sub><sup>SO</sup><sub><sup>4</sup></sub><sup>)</sup>/<sub>(6,02 × 10²³)</sub></p><p>mol H<sub>2</sub>SO<sub>4 </sub>= <sup>(3,02 × 10²³)</sup>/<sub>(6,02 × 10²³)</sub></p><p>mol H<sub>2</sub>SO<sub>4 </sub>= <strong>0,5 mol</strong></p><ul><li>Mencari<strong> massa H<sub>2</sub>SO<sub>4</sub></strong></li></ul><p>Massa H<sub>2</sub>SO<sub>4 </sub>= mol H<sub>2</sub>SO<sub>4</sub> × Mr H<sub>2</sub>SO<sub>4</sub></p><p>Massa H<sub>2</sub>SO<sub>4 </sub>= 0,5 × 98</p><p>Massa H<sub>2</sub>SO<sub>4 </sub>= <strong>49 gram</strong></p><ul><li>Mencari<strong> volume H<sub>2</sub>SO<sub>4</sub></strong></li></ul><p>Volume H<sub>2</sub>SO<sub>4 </sub>= mol H<sub>2</sub>SO<sub>4</sub> × 22,4 </p><p>Volume H<sub>2</sub>SO<sub>4 </sub>= 0,5 × 22,4 </p><p>Volume H<sub>2</sub>SO<sub>4 </sub>= <strong>11,2 L</strong></p><ul><li>Mencari <strong>molaritas H<sub>2</sub>SO<sub>4</sub></strong></li></ul><p>Molaritas H<sub>2</sub>SO<sub>4</sub> = <sup>(mol H</sup><sub><sup>2</sup></sub><sup>SO</sup><sub><sup>4</sup></sub><sup>)</sup>/<sub>(volume H2SO4)</sub></p><p>Molaritas H<sub>2</sub>SO<sub>4</sub> = <sup>0,5</sup>/<sub>11,2</sub></p><p>Molaritas H<sub>2</sub>SO<sub>4</sub> = <strong>0,04 M</strong></p><p> </p><p><strong>•• C<sub>2</sub>H<sub>2</sub>N</strong></p><p><strong>Diketahui : </strong>volume C<sub>2</sub>H<sub>2</sub>N = 44,8 L</p><p><strong>Ditanya : </strong>mol, massa, bilangan avogadro, molaritas, Mr</p><p><strong>Dijawab :</strong></p><ul><li>Mencari <strong>Mr C<sub>2</sub>H<sub>2</sub>N</strong></li></ul><p>Mr C<sub>2</sub>H<sub>2</sub>N = (Ar C × 2) + (Ar H × 2) + (Ar N × 1)</p><p>Mr C<sub>2</sub>H<sub>2</sub>N = (12 × 2) + (1 × 2) + (14 × 1)</p><p>Mr C<sub>2</sub>H<sub>2</sub>N = 24 + 2 + 14</p><p>Mr C<sub>2</sub>H<sub>2</sub>N = <strong>40 g/mol</strong></p><ul><li>Mencari<strong> mol C<sub>2</sub>H<sub>2</sub>N</strong></li></ul><p>mol C<sub>2</sub>H<sub>2</sub>N = <sup>(volume C</sup><sub><sup>2</sup></sub><sup>H</sup><sub><sup>2</sup></sub><sup>N)</sup>/<sub>22,4</sub></p><p>mol C<sub>2</sub>H<sub>2</sub>N = <sup>44,8</sup>/<sub>22,4</sub></p><p>mol C<sub>2</sub>H<sub>2</sub>N = <strong>2 mol</strong></p><ul><li>Mencari <strong>massa C<sub>2</sub>H<sub>2</sub>N</strong></li></ul><p>massa C<sub>2</sub>H<sub>2</sub>N = mol C<sub>2</sub>H<sub>2</sub>N × Mr C<sub>2</sub>H<sub>2</sub>N</p><p>massa C<sub>2</sub>H<sub>2</sub>N = 2 × 40</p><p>massa C<sub>2</sub>H<sub>2</sub>N = <strong>80 gram</strong></p><ul><li>Mencari <strong>bilangan avogadro C<sub>2</sub>H<sub>2</sub>N</strong></li></ul><p>jumlah partikel C<sub>2</sub>H<sub>2</sub>N = mol C<sub>2</sub>H<sub>2</sub>N × 6,02 × 10²³</p><p>jumlah partikel C<sub>2</sub>H<sub>2</sub>N = 2 × 6,02 × 10²³</p><p>jumlah partikel C<sub>2</sub>H<sub>2</sub>N = <strong>12,04 × 10²³ </strong></p><ul><li>Mencari <strong>molaritas C<sub>2</sub>H<sub>2</sub>N</strong></li></ul><p>Molaritas C<sub>2</sub>H<sub>2</sub>N = <sup>(mol C</sup><sub><sup>2</sup></sub><sup>H</sup><sub><sup>2</sup></sub><sup>N)</sup>/<sub>(volume C2H2N)</sub></p><p>Molaritas C<sub>2</sub>H<sub>2</sub>N = <sup>2</sup>/<sub>44,8</sub></p><p>Molaritas C<sub>2</sub>H<sub>2</sub>N = <strong>0,04 M</strong></p><p> </p><p>Selesai :')🙏</p>
•• H2SO4
Diketahui : bilangan avogadro H2SO4 = 3,02 × 10²³
Ditanya : mol, massa, molaritas, Mr, Volume
Dijawab :
- Mencari Mr H2SO4
Mr H2SO4 = (Ar H × 2) + (Ar S × 1) + (Ar O × 4)
Mr H2SO4 = (1 × 2) + (32 × 1) + (16 × 4)
Mr H2SO4 = 2 + 32 + 64
Mr H2SO4 = 98 g/mol
- Mencari mol H2SO4
mol H2SO4 = (jumlah partikel H2SO4)/(6,02 × 10²³)
mol H2SO4 = (3,02 × 10²³)/(6,02 × 10²³)
mol H2SO4 = 0,5 mol
- Mencari massa H2SO4
Massa H2SO4 = mol H2SO4 × Mr H2SO4
Massa H2SO4 = 0,5 × 98
Massa H2SO4 = 49 gram
- Mencari volume H2SO4
Volume H2SO4 = mol H2SO4 × 22,4
Volume H2SO4 = 0,5 × 22,4
Volume H2SO4 = 11,2 L
- Mencari molaritas H2SO4
Molaritas H2SO4 = (mol H2SO4)/(volume H2SO4)
Molaritas H2SO4 = 0,5/11,2
Molaritas H2SO4 = 0,04 M
•• C2H2N
Diketahui : volume C2H2N = 44,8 L
Ditanya : mol, massa, bilangan avogadro, molaritas, Mr
Dijawab :
- Mencari Mr C2H2N
Mr C2H2N = (Ar C × 2) + (Ar H × 2) + (Ar N × 1)
Mr C2H2N = (12 × 2) + (1 × 2) + (14 × 1)
Mr C2H2N = 24 + 2 + 14
Mr C2H2N = 40 g/mol
- Mencari mol C2H2N
mol C2H2N = (volume C2H2N)/22,4
mol C2H2N = 44,8/22,4
mol C2H2N = 2 mol
- Mencari massa C2H2N
massa C2H2N = mol C2H2N × Mr C2H2N
massa C2H2N = 2 × 40
massa C2H2N = 80 gram
- Mencari bilangan avogadro C2H2N
jumlah partikel C2H2N = mol C2H2N × 6,02 × 10²³
jumlah partikel C2H2N = 2 × 6,02 × 10²³
jumlah partikel C2H2N = 12,04 × 10²³
- Mencari molaritas C2H2N
Molaritas C2H2N = (mol C2H2N)/(volume C2H2N)
Molaritas C2H2N = 2/44,8
Molaritas C2H2N = 0,04 M
Selesai :')🙏
· 0.0 (0)
Iklan
Mau jawaban yang terverifikasi?
Tanya ke AiRIS
Yuk, cobain chat dan belajar bareng AiRIS, teman pintarmu!
LATIHAN SOAL GRATIS!
Drill Soal
Latihan soal sesuai topik yang kamu mau untuk persiapan ujian
Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!
