Kakk aku bingung :(

<p>Betul, (f-¹ o g-¹)(x) adalah (g-¹ o f-¹)(x)</p><p>&nbsp;</p><p><strong>Diketahui :&nbsp;</strong></p><ul><li>f(x) = ^{(5x - 3)}/_{(x - 2)}</li><li>g(x) = ^{(2x - 3)}/_{(x - 5)}</li></ul><p><strong>Ditanya : </strong>(f-¹ o g-¹)(x) = (g-¹ o f-¹)(x)</p><p><strong>Dijawab :</strong></p><p>Rumus Invers → f(x) = ^{(ax + b)}/_{(cx + d)}menjadi f-¹(x) = ^{(-dx + b)}/_{(cx - a)}</p><p>f(x) = ^{(5x - 3)}/_{(x - 2)}→ a = 5, b = -3, c = 1, d = -2</p><p>f-¹(x) = ^{(-(-2)x + (-3))}/_{(1x - 5)}</p><p><strong>f-¹(x) = ^{(2x - 3)}/_{(x - 5)}</strong></p><p>g(x) = ^{(2x - 3)}/_{(x - 5)}→ a = 2, b = -3, c = 1, d = -5</p><p>g-¹(x) = ^{(-(-5)x + (-3))}/_{(1x - 2)&nbsp;}</p><p><strong>g-¹(x) = ^{(5x - 3)}/_{(x - 2)&nbsp;}</strong></p><p>&nbsp;</p><p>(f-¹ o g-¹)(x) = (g-¹ o f-¹)(x)</p><p>&nbsp; f-¹(g-¹)(x)) = g-¹ (f-¹)(x))</p><p>f-¹(^{(5x - 3)}/_{(x - 2)}) = g-¹ (^{(2x - 3)}/_{(x - 5)})</p><ul><li>2(^{(5x - 3)}/_{(x - 2)}) - 3 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;5(^{(2x - 3)}/_{(x - 5)}) - 3</li><li>–––––––––––– &nbsp; = &nbsp; &nbsp;––––––––––––</li><li>(^{(5x - 3)}/_{(x - 2)}) - 5 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; (^{(2x - 3)}/_{(x - 5)}) - 2</li></ul><p>&nbsp;</p><ul><li>^{2(5x - 3) - 3(x -2)}/_{(x - 2)} &nbsp; &nbsp; &nbsp;^{5(2x - 3) - 3(x - 5)}/_{(x - 5)}</li><li>–––––––––––– &nbsp; = &nbsp; &nbsp;––––––––––––</li><li>^{(5x - 3) - 5(x - 2)}/_{(x - 2)} &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;^{(2x - 3) - 2(x - 5)}/_{(x - 5)}</li></ul><p>&nbsp;</p><ul><li>&nbsp; &nbsp;<u>10x - 6 - 3x + 6 &nbsp;</u> &nbsp; &nbsp; = &nbsp; &nbsp;&nbsp;<u>10x - 15 - 3x + 15</u></li><li>&nbsp; &nbsp;5x - 3 - 5x + 10 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;2x - 3 - 2x + 10</li></ul><p>^7x/₇= ^7x/₇</p><p>&nbsp; &nbsp; &nbsp;x = x</p><p>&nbsp;</p><p>Selesai :')🙏</p><p>Semoga bisa paham, yang tanda titik titik abaikan saja ya :3</p>