Jika p=[(1)(5)], q=[(−2)(4)] dan r=[(−3)(−1)] Carilah hasil operasi vektor dari: 2p+q

Jawaban yang benar adalah [(0) (14)]. Sifat : Jika vektor a = [(x1) (y1)] dan vektor b = [(x2)(y2], maka : k · a = [(kx1) (ky1)] dengan k = skalar a + b = [(x1+x2) (y1+y2)] p = [(1) (5)] q = [(-2) (4)] r = [(-3) (-1)] 2p + q = 2 [(1) (5)] + [(-2) (4)] = [(2·1) (2·5)] + [(-2) (4)] = [(2) (10)] + [(-2) (4)] = [(2+(-2)) (10+4)] = [(0) (14)] Jadi, 2p + q= [(0) (14)].