jika f'(x) = 9x² -12x + 2 dan f(-1) = 0, maka f(0) =

Jawabannya adalah 11 Konsep : ∫ axⁿ dx = a/(n+1) . xⁿ⁺¹ + c Jawab : ∫ 9x² -12x + 2 dx = 9/(2+1) x²⁺¹ - 12/(1+1) x¹⁺¹ + 2/(0+1) x⁰⁺¹ + c = 9/3 x³ - 12/2 x² + 2x + c = 3x³ - 6x² + 2x + c Maka f(x) = 3x³ - 6x² + 2x + c f(-1) = 0 -> 3(-1)³ - 6(-1)² + 2(-1) + c = 0 -3 - 6 - 2 + c = 0 - 11 + c = 0 c = 11 f(x) = 3x³ - 6x² + 2x + 11 f(0) = 3(0)³ - 6(0)² + 2(0) + 11 = 0 - 0 + 0 + 11 = 11 Jadi f(0) = 11