Hitung nilai dari ^(3)log343 . 6log1/81 . ^(7)log216

<p>Jawaban : -36</p><p>&nbsp;</p><p>Ingat kembali:</p><ul><li>^alog bⁿ = n . ^alog b</li><li>^alog a = a</li><li>^alog b . ^blog c = ^alog c</li></ul><p>&nbsp;</p><p>Maka:</p><p>³log 343 . ⁶log 1/81 . ⁷log 216</p><p>= ³log 7³ . ⁶log 1/3⁴ . ⁷log 6³</p><p>= (3) . (3) . ³log 7 . ⁶log 3^-4 . ⁷log 6</p><p>= 9 . (-4) . &nbsp;³log 7 . ⁶log 3 . ⁷log 6</p><p>= (-36) . ³log 7 . ⁷log 6 . ⁶log 3</p><p>= (-36) . ³log 3</p><p>= (-36) . 1</p><p>= -36</p><p>&nbsp;</p><p>Jadi, ³log 343 . ⁶log 1/81 . ⁷log 216 = -36.</p>