Gambarlah grafik dari persamaan fungsi kuadrat berikut : y = x² + 16x - 17

<p>y = x² + 16x - 17&nbsp;</p><p><strong>Langkah 1 </strong>: Mencari titik potong sumbu x, maka y = 0</p><p>x² + 16x - 17&nbsp;= 0</p><p>(x - 1)(x + 17) = 0</p><p>x₁ = 1 atau x₂ = -17</p><p>Grafik memotong sumbu x di (1,0) dan (-17,0)</p><p>&nbsp;</p><p><strong>Langkah 2&nbsp;</strong> : Mencari titik potong sumbu y, maka x = 0</p><p>y = x² + 16x - 17&nbsp;</p><p>y = (0)² + 16(0) - 17&nbsp;</p><p>y = -17</p><p>Grafik memotong sumbu y di (0,-17)</p><p>&nbsp;</p><p><strong>Langkah 3</strong> : Mencari sumbu simetri dan titik puncak (titik minimum)</p><p>y = x² + 16x - 17&nbsp;</p><p>a = 1; b = 16 dan c = -17</p><p>Sumbu simetri (x_p) = -b/2a</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= -16/2(1)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= -16/2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= -8 &nbsp; &nbsp;</p><p>y_p= (b² - 4ac)/(-4a)</p><p>&nbsp; &nbsp; &nbsp;= (16² - 4(1)(-17))/(-4(1))</p><p>&nbsp; &nbsp; &nbsp;= (256 + 68)/-4</p><p>&nbsp; &nbsp; &nbsp;= 324/-4</p><p>&nbsp; &nbsp; &nbsp;= -81</p><p>Titik puncak = (x_p,y_p)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= (-8, -81)</p><p>&nbsp;</p><p>Gambarnya ada dibawah :&nbsp;</p><p>&nbsp;</p>