Ditunggu jawabannya

<p><strong>Pembahasan</strong></p><p>2^2x+3- 8.2^x+1+ 8 = 0 &nbsp; &nbsp; &nbsp; &nbsp;(i)&nbsp;</p><p>&nbsp;</p><p>Dimisalkan y = 2^{x &nbsp; &nbsp; &nbsp;&nbsp;}(ii)&nbsp;</p><p>2^2x+3= 2^2x⁠⁠⁠⁠. 2^{3 &nbsp;}——&gt; y². 8</p><p>2^x+1= &nbsp;2^x.2 &nbsp; &nbsp; ——&gt; 2y</p><p>maka persamaan (i) menjadi&nbsp;</p><p>8y² - 8.2y + 8 = 0</p><p>&lt;=&gt; y² - 2y + 1 = 0</p><p>&lt;=&gt; (y - 1)² = 0</p><p>&lt;=&gt; y = 1</p><p>&nbsp;</p><p>(ii) &nbsp;2^x= 1 maka x = 0</p><p>&nbsp;</p><p>Nilai x yg menuhi pd persamaan tsb adalah <strong>0</strong></p><p>&nbsp;</p>