Diketahui f(x) = 3 - 2x dan (fog)(x)=x²-x+4. Tentukan g(x),(gof)(x), dan (gof)(-1).

Halo Novi, aku bantu jawab ya Jawaban: g(x) = -1/2 (x² - x + 1), (g o f)(x) = -1/2 (4x² - 10x + 7) dan (g o f)(-1) = -21/2 Ingat! (f o g)(x) = f(g(x)) (g o f)(x) = g(f(x)) Pembahasan: f(x) = 3 - 2x (f o g)(x) = x² - x + 4 f(g(x)) = x² - x + 4 3 - 2g(x) = x² - x + 4 -2g(x) = x² - x + 4 - 3 -2g(x) = x² - x + 1 g(x) = -1/2 (x² - x + 1) (g o f)(x) = g(f(x)) = g(3 - 2x) = -1/2 ((3 - 2x)² - (3 - 2x) + 1) = -1/2 (9 - 12x + 4x² - 3 + 2x + 1) = -1/2 (4x² - 10x + 7) (g o f)(-1) = -1/2 (4(-1)² - 10(-1) + 7) = -1/2 (4 + 10 + 7) = -1/2 (21) = -21/2 Dengan demikian diperoleh g(x) = -1/2 (x² - x + 1), (g o f)(x) = -1/2 (4x² - 10x + 7) dan (g o f)(-1) = -21/2 Semoga membantu 🤗