Benda tingginya 2 cm diletakkan 6 cm di depan lensa cekung yang jarak fokusnya 2 cm, maka tentukan: a. Jarak bayangan b. Perbesaran bayangan c. Tinggi bayangan d. Sifat bayangan e. Kekuatan lensa Tolong di bantu kak

<p>Diketahui :</p><ul><li>ho = 2 cm</li><li>So = 6 cm</li><li>f = 2 cm</li></ul><p>Penyelesaian :</p><p>a. Jarak bayangan (Si)</p><p>&nbsp; &nbsp; &nbsp;1/f = 1/So + 1/Si</p><p>&nbsp; &nbsp; &nbsp;1/Si = 1/f - 1/So</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1/2 - 1/6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 3/6 - 1/6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 2/6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1/3</p><p>&nbsp; &nbsp; Si = 3 cm</p><p>&nbsp; &nbsp; &nbsp;Jadi jarak bayangan benda adalah 3 cm</p><p>&nbsp;</p><p>b. Perbesaran benda</p><p>&nbsp; &nbsp; &nbsp;M = |Si/So|</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = |3/6|</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1/2 kali</p><p>&nbsp; &nbsp; &nbsp; Perbesaran benda adalah 1/2 kali</p><p>&nbsp;</p><p>c. Tinggi Bayangan</p><p>&nbsp; &nbsp; &nbsp;hi = M x ho</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1/2 x 2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1 cm</p><p>&nbsp; &nbsp; &nbsp; Jadi Tinggi bayangan &nbsp;adalah 1 cm</p><p>&nbsp;</p><p>d. Sifat bayangan</p><p>&nbsp; &nbsp; &nbsp; Sifat bayangannya adalah&nbsp;</p><p>&nbsp; &nbsp; &nbsp; - Nyata</p><p>&nbsp; &nbsp; &nbsp; - Terbalik</p><p>&nbsp; &nbsp; &nbsp; - Diperkecil</p><p>&nbsp;</p><p>e. Kekuatan lensa</p><p>&nbsp; &nbsp; &nbsp;P = 100/f</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 100/2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 50 dioptri</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</p>