Rueda A

30 September 2023 06:19

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Rueda A

30 September 2023 06:19

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Barisa geometri atau deret ukur memiliki rasio atau pembanding (r) =1/2 suku pertama adalah 512, hitunglah? a. Suku ke-6 dan suku ke-8 b. Jumlah Suku ke 10 dan 12

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30 September 2023 09:14

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<p>Diketaui :</p><ul><li>r = 1/2</li><li>a = 512</li></ul><p>&nbsp;</p><p>Mari kita bahas :</p><p>a. Mencari Suku ke-6 dan suku ke-8</p><p>&nbsp; &nbsp; &nbsp;U<sub>n</sub> = ar<sup>n-1</sup></p><p>&nbsp; &nbsp; &nbsp;U<sub>6</sub> = 512.(1/2)<sup>6-1</sup></p><p><sup>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</sup>= 512. (1/2)<sup>5</sup></p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 512. (1/32)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 16</p><p>&nbsp; &nbsp; &nbsp;&nbsp;</p><p>&nbsp; &nbsp; &nbsp; U<sub>8</sub> = 512.(1/2)<sup>8-1</sup></p><p><sup>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</sup>= 512. (1/2)<sup>7</sup></p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 512. (1/128)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 4</p><p>&nbsp; &nbsp; Jadi, suku ke-6 = <strong>16</strong> dan suku ke-8 =<strong> 4</strong></p><p>&nbsp;</p><p>b. Mencari Jumlah Suku ke 10 dan 12</p><p>&nbsp; &nbsp; &nbsp;S<sub>n </sub>= a(1 - r<sup>n</sup>)/(1 - r)</p><p>&nbsp; &nbsp; &nbsp;S<sub>10 </sub>= 512(1 - (1/2)<sup>10</sup>)/(1 - 1/2)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 512(1 - 1/1024))/(1/2)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 512(1023/1024))/(1/2)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 511,5 / (1/2)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 511,5 x 2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1023</p><p>&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; S<sub>12 </sub>= 512(1 - (1/2)<sup>12</sup>)/(1 - 1/2)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 512(1 - 1/4096))/(1/2)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 512(4095/4096))/(1/2)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 511,875 / (1/2)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 511,875 x 2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 1023,75</p><p>&nbsp; &nbsp;Jadi, Jumlah Suku ke-10 = <strong>1023</strong> dan suku ke-12 = <strong>1023,75</strong></p>

Diketaui :

  • r = 1/2
  • a = 512

 

Mari kita bahas :

a. Mencari Suku ke-6 dan suku ke-8

     Un = arn-1

     U6 = 512.(1/2)6-1

               = 512. (1/2)5

           = 512. (1/32)

           = 16

      

      U8 = 512.(1/2)8-1

               = 512. (1/2)7

           = 512. (1/128)

           = 4

    Jadi, suku ke-6 = 16 dan suku ke-8 = 4

 

b. Mencari Jumlah Suku ke 10 dan 12

     Sn = a(1 - rn)/(1 - r)

     S10 = 512(1 - (1/2)10)/(1 - 1/2)

            = 512(1 - 1/1024))/(1/2)

            = 512(1023/1024))/(1/2)

            = 511,5 / (1/2)

            = 511,5 x 2

            = 1023

 

        S12 = 512(1 - (1/2)12)/(1 - 1/2)

               = 512(1 - 1/4096))/(1/2)

               = 512(4095/4096))/(1/2)

               = 511,875 / (1/2)

               = 511,875 x 2

               = 1023,75

   Jadi, Jumlah Suku ke-10 = 1023 dan suku ke-12 = 1023,75


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