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Question

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Arin R · Accepted Answer

4. L I (½ lingkaran) = ½ × π × r²
                                     = ½ × 3,14 × 10²
                                     = ½ × 3,14 × 100
                                     = 157 cm²
     L II (persegi) = s × s
                              = 20 × 20
                              = 400 cm²
     L III (segitiga) = ½ × a × t
                                = ½ × 15 × 20
                                = 150 cm²
     L total = L I + L II + L III
                  = 157 + 400 + 150
                  = 707 cm²

5. L1 (persegi panjang) = p × l
                                             = 22 × 14 
                                             = 308 cm²
     L2 (segitiga) = ½ × a × t
                              = ½ × 3 × 22
                              = 33 cm²
     L3 = L2 = 33 cm²
     
     L total = L1 + L2 + L3
                  = 308 + 33 + 33
                  = 374 cm²

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