Alas sebuah limas berbentuk persegi dengan panjang sisinya 12 cm. Jika tinggi limas 8 cm, tentukan: a. tinggi segitiga pada sisi tegak, b. luas TBC, c. luas permukaan limas!

<p>a.Tf &nbsp; = √8²+6²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = √64+36</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = √100</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 10cm</p><p>b. L &nbsp; = a x t / 2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 6 x 10 / 7</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 60 cm²</p><p>c. Lp = luas alas+ luas sisi tegak &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = (12 x12) + 4(60)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 144 + 240</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 384 cm²</p>