alas sebuah Limas berbentuk persegi dengan panjang sisi alas adalah 20cm. tinggi sisi tegaknya adalah 25cm. luas permukaan Limas segi empat tersebut adalah......cm²

<p>L limas = L alas + jumlah L sisi tegak</p><p>√ alas limas berbentuk persegi dgn sisi : 20cm</p><p>√ sisi tegak limas berbentuk segitiga dgn alas : 20cm, tinggi sisi tegak = 25cm</p><p>Mencari L alas persegi = s² = 20² = 400cm²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;L sisi tegak segitiga = ½x alas x tinggi</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= ½ x 20 x25</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 250cm²</p><p>Jadi ,&nbsp;</p><p>L limas = L alas + jumlah L sisi tegak</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 400+ (4x250) &nbsp;==&gt; sisi tegak limas segi empat ada 4&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 400 + 1.000</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; =1.400cm²</p>