DARRELL R

27 November 2022 10:41

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DARRELL R

27 November 2022 10:41

Pertanyaan

Air teh bersuhu 80°C melepaskan kalor sebanyak 8,4 kJ . Diketahui massa air teh 200 gram dan massa jenisnya 4.200 J/kg°C. Suhu air teh setelah melepaskan kalo r sebesar ....°C.

Air teh bersuhu 80°C melepaskan kalor sebanyak 8,4 kJ. Diketahui massa air teh 200 gram dan massa jenisnya 4.200 J/kg°C. Suhu air teh setelah melepaskan kalor sebesar ....°C.


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Ivona A

27 November 2022 12:47

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<p>8400 J = 1/5 x 4200 x delta t<br>8400 J = 840 x delta t<br>Delta t = 8400 : 840<br>Delta t = 10 derajat celcius</p><p>Melepaskan kalor = dikurangi suhunya</p><p>80 - 10 = 70 derajat celcius</p>

8400 J = 1/5 x 4200 x delta t
8400 J = 840 x delta t
Delta t = 8400 : 840
Delta t = 10 derajat celcius

Melepaskan kalor = dikurangi suhunya

80 - 10 = 70 derajat celcius


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Intan D

06 Desember 2022 11:52

<p>Dik: M=200 gram = 0,2 kg &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; c=4.200 j /kg°c &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Q= 8,4 kj= 8.400 joule &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; dit: suhu akhir teh ,∆T= ....? &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Jawab=. &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Q=m.c.∆T &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;8.400=0,2.4.200.∆T &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ∆T=8.400:840 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ∆T=10°c &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Jdi suhu air teh setelahelepaskn kalor sbsr : 80°c-10°c=70°c</p><p>&nbsp;</p>

Dik: M=200 gram = 0,2 kg                                                       c=4.200 j /kg°c                                                                  Q= 8,4 kj= 8.400 joule                                             dit: suhu akhir teh ,∆T= ....?                               Jawab=.                                                             Q=m.c.∆T                                        8.400=0,2.4.200.∆T                                         ∆T=8.400:840                                                     ∆T=10°c                                                                       Jdi suhu air teh setelahelepaskn kalor sbsr : 80°c-10°c=70°c

 


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