tuliskan10 Suku pertains bilangan segitiga

Halo Ani, kakak bantu jawab ya :) Jawaban : 1, 3, 6, 10, 15, 21, 28, 36, 45, dan 55. Perhatikan penjelaan berikut ya. Ingat rumus suku (pola) ke n pada pola bilangan segitiga yaitu Tn = (1/2)n(n + 1). Dengan keterangan : n : banyak suku. Tn : bilangan ke n. Tentukan 10 suku pertama bilangan segitiga. T1 = (1/2)(1) x (1 + 1) = (1/2) x 2 = 1 T2 = (1/2)(2) x (2 + 1) = 1 x 3 = 3 T3 = (1/2)(3) x (3 + 1) = (3 x 4)/2 = 12/2 = 6 T4 = (1/2)(4) x (4 + 1) = 2 x 5 = 10 T5 = (1/2)(5) x (5 + 1) = (5 x 6)/2 = 30/2 = 15 T6 = (1/2)(6) x (6 + 1) = 3 x 7 = 21 T7 = (1/2)(7) x (7 + 1) = (7 x 8)/2 = 56/2 = 28 T8 = (1/2)(8) x (8 + 1) = 4 x 9 = 36 T9 = (1/2)(9) x (9 + 1) = (9 x 10)/2 = 90/2 = 45 T10 = (1/2)(10) x (10 + 1) = 5 x 11 = 55 Jadi, 10 suku pertama bilangan segitiga adalah 1, 3, 6, 10, 15, 21, 28, 36, 45, dan 55.