tolong ya

<p>f(x) = x² + 4x - 12</p><p>titik potong dengan sumbu x&nbsp;</p><p>jika y = 0&nbsp;</p><p>maka,</p><p>&nbsp;</p><p>&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; x²+ 4x - 12 &nbsp;= 0</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; (x+6)(x-2) = 0</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; x = -6 atau x = 2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; jadi absis -6 atau 2 (A)</p>