Tolong dijawab dong temen2🙏

<p>Jawaban&nbsp;</p><p>Nilai max. f(x)&nbsp;</p><p><strong>a = 3, b = 5/6 π</strong></p><p>Tidak ada opsi jawaban yang benar&nbsp;</p><p>&nbsp;</p><p>&nbsp;</p><p>&nbsp;</p><p><strong>Pembahasan&nbsp;</strong></p><p>f(x) = 2 sin (x - ⅓π) + 1</p><p>&nbsp;</p><p>Mencari nilai max. dgn cara menurunkan fungsi tsb, untuk mencari titik stasioner (titik balik)&nbsp;</p><p>f'(x) = 2 cos (x - π/3)</p><p>&lt;=&gt;0 = 2 cos (x - π/3)</p><p>&lt;=&gt; cos (x - π/3) = 0</p><p>&lt;=&gt; x = 5/6 π atau x = 11/6 π (❌ akan bernilai negatif)&nbsp;</p><p>Nilai x yg memenuhi = 5/6π ——&gt; &nbsp;nilai b</p><p>&nbsp;</p><p>f(5/6π) = 2 sin (5/6π - ⅓π) + 1</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 2 sin ½π + 1</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 2.1 + 1</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 3 ——&gt; nilai a</p><p>&nbsp;</p><p>Lihat pd foto terlampir sbg gambaran untuk fungsi tsb</p><p>&nbsp;</p>