Tentukan akar-akar persamaan 8x^(2)+19 x+5=0

Jawaban: (–19 – √201)/16 dan (–19 + √201)/16 Konsep! Akar-akar persamaan kuadrat ax² + bx + c = 0 yaitu x12 = (–b ± √(b² – 4ac))/(2a). Pembahasan: 8x² + 19x + 5 = 0 Dengan a = 8, b = 19 dan c = 5 x12 = (–b ± √(b² – 4ac))/(2a) x12 = (–19 ± √(19² – 4(8)(5)))/(2(8)) x12 = (–19 ± √(361 – 160))/16 x12 = (–19 ± √201)/16 x1 = (–19 – √201)/16 x2 = (–19 + √201)/16 Jadi, akar-akarnya adalah (–19 – √201)/16 dan (–19 + √201)/16.