Sederhanakan bentuk pangkat berikut, kemudian nyatakan dalam pangkat positif. a.(3^(-7) x 3^(6))/(3^(-5) x 3^(4)) b. (-2a^(3)b^(-1)) : (2a^(-2)b^(3))^(2) c. (x^(2)/y)^(2) · (2x^(4)/y^(2))^(-1)

<p>Jawaban :&nbsp;</p><p>a.(3^(-7) x 3^(6))/(3^(-5) x 3^(4)) = 1</p><p>b. (-2a^(3)b^(-1)) : (2a^(-2)b^(3))^(2) = (-a^(7))/(2b^(7))</p><p>c. (x^(2)/y)^(2) · (2x^(4)/y^(2))^(-1) = 1/2</p><p>&nbsp;</p><p>Ingat!<br>(a^(m))^(n) = a^(mn)</p><p>a^(m) x a^(n) = a^(m+n)</p><p>a^(m) : a^(n) = a^(m-n)</p><p>(ab)^m = a^m x b^m&nbsp;</p><p>(a/b)^m = a^m/b^m</p><p>a^(0) = 1, jika a ≠0</p><p>a^(-n) = 1/a^(n)</p><p>&nbsp;</p><p>Sehingga&nbsp;</p><p>a.(3^(-7) x 3^(6))/(3^(-5) x 3^(4))&nbsp;</p><p>= (3^(-7) x 3^(6))/(3^(-5) x 3^(4))&nbsp;</p><p>= (3^(-7+6))/(3^(-5+4))&nbsp;</p><p>= (3^(-1))/(3^(-1))&nbsp;</p><p>= 3^(-1-(-1))&nbsp;</p><p>= 3^(0)&nbsp;</p><p>= 1</p><p>&nbsp;</p><p>b. (-2a^(3)b^(-1)) : (2a^(-2)b^(3))^(2)&nbsp;</p><p>= (-2a^(3)b^(-1)) : (4a^(-4)b^(6))</p><p>= (-a^(3-(-4))b^(-1-6))/(2)</p><p>= (-a^(7)b^(-7))/(2)</p><p>= (-a^(7))/(2b^(7))</p><p>&nbsp;</p><p>c. (x^(2)/y)^(2) · (2x^(4)/y^(2))^(-1)</p><p>= (x^(4))/(y^(2)) · (2^(-1)x^(-4))/(y^(-2))</p><p>= (x^(4))/(y^(2)) · (x^(-4))/(2y^(-2))</p><p>= (x^(4)x^(-4))/(2y^(2)y^(-2))</p><p>= (x^(4+(-4)))/(2y^(2+(-2)))</p><p>= (x^(0))/(2y^(0))</p><p>= 1/2</p><p><br>Jadi, jawabannya adalah&nbsp;</p><p>a.(3^(-7) x 3^(6))/(3^(-5) x 3^(4)) = 1</p><p>b. (-2a^(3)b^(-1)) : (2a^(-2)b^(3))^(2) = (-a^(7))/(2b^(7))</p><p>c. (x^(2)/y)^(2) · (2x^(4)/y^(2))^(-1) = 1/2</p>