sebuah Limas segiempat T.ABCD dengan panjang sisi 20cm memiliki tinggi 24cm berapa luas permukaan Limas

<p>Diket : panjang sisi alas (s &nbsp;= 20cm</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; tinggi limas (t &nbsp;= 24cm</p><p>Ditanya : L permukaan limas?&nbsp;</p><p>Jawab : L permukaan limas = L alas + jumlah L sisi tegak</p><p>√alas limas berbentuk persegi =&gt;L = s² = 20²= 400cm²</p><p>√sisi tegak limas ada 4 sisi yg sama besar berbentuk segitiga =&gt; L = ½ x alas x tinggi segitiga = ½ x 20x 26 = 260cm²</p><p>&lt;=&gt;Tinggi segitiga dicari dari rumus phytagoras (ada di gambar)&nbsp;</p><p>Jadi</p><p>L permukaan limas = L alas + (4 x L segitiga)&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 400 + (4 x 260&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 400 + 1060</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1460cm² &nbsp; &nbsp;&nbsp;</p>