Pertanyaan kamu a.sebuah benda ketinggian 10 m dari tanah energi potensial 6000 Joule benda jatuh 2m kebawah dari kedudukan mula-mula hitunglah energi potensial yang dimiliki benda tersebut sekarang b. hitunglah energi kinetik turun 2 meter C. hitunglah energi mekanik turun 2 meter

<p>a). Ep1 = m . g . h = 6000 joule</p><p>&nbsp; &nbsp; &nbsp; m . 10 . 10 = 6000</p><p>&nbsp; &nbsp; &nbsp; m = 6000/100 = 60 kg</p><p>&nbsp; &nbsp; &nbsp; Ep2 = 60 . 10 . (10-2) = 600 . 8 = 4800 joule</p><p>&nbsp;</p><p>b). Energi kinetik = ½ m.v²(v belum diketahui)</p><p>&nbsp; &nbsp; &nbsp; &nbsp;Ek = ½ 60 x v²</p><p>&nbsp; &nbsp; &nbsp; &nbsp;v² = 2 . g . h</p><p>&nbsp; &nbsp; &nbsp; &nbsp;v² = 2 . 10 . 10 = 200</p><p>&nbsp; &nbsp; &nbsp; Ek = 30 x 200</p><p>&nbsp; &nbsp; &nbsp; Ek = 6000</p><p>&nbsp;</p><p>c). Energi mekanik = Ep + Ek&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 4800 + 6000</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 10800 Joule</p><p>&nbsp;</p><p>Semoga membantu, mohon maaf jika salah&nbsp;</p>