pembakaran sempurna 32 gram cuplikan belerang menghasilkan 48 gram belerang trioksida. menurut persamaan kimia berikut 2S + O2 menjadi S03. tentukan kadar belerang dalam cuplikan tersebut

<p>2S + 3 O₂ &nbsp;--&gt; &nbsp;2 SO₃</p><p>&nbsp;</p><p>48 gram SO₃.</p><p>massa S = Ar S / Mr SO₃ x massa SO₃</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 32 / 80 x 48</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 0,4 x 48</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= &nbsp;19,2 gram</p><p>Kadar S dalam cuplikan : &nbsp;19,2 &nbsp;/ 32 x 100%</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = &nbsp;&nbsp;<strong>60%</strong></p>