Tina S
28 Mei 2024 05:04
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Tina S
28 Mei 2024 05:04
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Mohon bantuannya kak/bg🙏
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Andrew F
28 Mei 2024 07:33
1/(x1 + 1) + 1/(x2 + 1)
(x2 + 1)/(x1 + 1)(x2 + 1) + (x1 + 1)/(x1 + 1)(x2 + 1)
((x2 + 1) + (x1 + 1))/(x1 + 1)(x2 + 1)
(x1 + x2 + 2)/((x1 × x2) + ((x1 × 1) + (1 × x2)) + (1 × 1))
(x1 + x2 + 2)/(x1x2 + (x1 + x2) + 1)
Bentuk umum persamaan kuadrat :
ax² + bx + c = 0
x1 + x2 = -b/a
x1 × x2 = x1x2 = c/a
Maka :
x² + 4x - 3 = 0
(1)x² + (4)x + (-3) = 0
a = 1
b = 4
c = -3
x1 + x2 = -b/a
x1 + x2 = -4/1
x1 + x2 = -4.
x1 × x2 = x1x2 = c/a
x1x2 = c/a
x1x2 = -3/1
x1x2 = -3.
(x1 + x2 + 2)/(x1x2 + (x1 + x2) + 1)
(-4 + 2)/(-3 + (-4) + 1)
(-2)/(-6) = 1/3. (A)
Jadi, hasilnya adalah 1/3. (A)
Semoga membantu.
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