Minta tolong dong

<ul><li><strong>Mencari tinggi tinggi sisi tegak pada limas (ts)</strong></li></ul><p>&nbsp; &nbsp; &nbsp; ts² &nbsp;= TO² + (EF : 2)²&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 8² + (12 : &nbsp;2)²&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 64 + 36</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 100</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;ts = √100</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 10 cm</p><ul><li><strong>Mencari luas sisi tegak limas (L1)</strong></li></ul><p>&nbsp; &nbsp; &nbsp; L1 = 4 x luas segitiga tegak</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 4 x 1/2 x EF x ts</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = &nbsp;2 x EF x ts</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 2 x 12 x 10</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 240 cm²&nbsp;</p><ul><li><strong>Mencari luas permuaan balok (L2)</strong></li></ul><p>&nbsp; &nbsp; &nbsp; &nbsp;L2 = luas alas + (keliling alas x tinggi)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= (EF X FG) + (EF + FG + GH + EH) x GC)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= (12 x 12) + (12 + 12 + 12 + 12) x 15)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 144 + (48 x 15)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 144 + 720</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 864 cm²</p><ul><li><strong>Luas Permukaan bangun&nbsp;</strong></li></ul><p>&nbsp; &nbsp; &nbsp; L = L1 + L2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 240 + 864</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = <strong>1.104 cm²</strong></p><p>&nbsp;</p>