Jika akar-akar (p-2)x^{2}-p^{2}x+(3p-2)=0 adalah a dan beta jika alphabeta=alpha+beta . maka nilai p=

<p>Jawaban &nbsp;<strong>p = 1&nbsp;</strong></p><p>&nbsp;</p><p><strong>Pembahasan&nbsp;</strong></p><p>(p-2)x² - p²x + (3p-2) = 0</p><p>Diketahui: α.β = α + β</p><p>&nbsp;</p><p>x1 + x2 = -b/a</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = - (-p²)/(p-2)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = p²/(p-2)</p><p>&nbsp;</p><p>x1.x2 = c/a</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= (3p-2)/(p-2)</p><p>&nbsp;</p><p>&nbsp;(3p-2)/(p-2) = p²/(p-2)</p><p>&lt;=&gt; 3p - 2 = p²</p><p>&lt;=&gt; p² - 3p + 2 = 0</p><p>&lt;=&gt; (p - 2)(p - 1) = 0</p><p>&lt;=&gt; p = 1 atau p = 2</p><p>&nbsp;</p><p>p ≠ 2 krn penyebut (p-2) akan bernilai 0 sehingga hasil bagi menjadi tak terdefinisi</p><p>&nbsp;</p>