Navisha P
14 Januari 2023 09:26
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Navisha P
14 Januari 2023 09:26
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M. Claudia
Mahasiswa/Alumni Universitas Nusa Cendana Kupang
31 Januari 2023 13:25
<p>Jawaban yang benar adalah (x¹¹z²)/(y⁸).</p><p> </p><p>Ingat!</p><p>a⁻¹ = 1/a</p><p>(a<sup>m</sup>)<sup>n</sup> = a<sup>mn</sup></p><p>(a<sup>m</sup>)·(a<sup>n</sup>) = a<sup>m+n</sup></p><p>(a<sup>m</sup>)/(a<sup>n</sup>) = a<sup>m-n</sup></p><p> </p><p>Berdasarkan soal, diperoleh:</p><p>[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x⁻¹y⁻²⁻<sup>(</sup>⁻³<sup>)</sup>)/(z²)]⁻² · [(x²⁻<sup>(</sup>⁻¹<sup>)</sup>z⁻³⁻<sup>(</sup>⁻²<sup>)</sup>)/(y²)]³</p><p>[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x⁻¹y⁻²⁺³)/(z²)]⁻² · [(x²⁺¹z⁻³⁺²)/(y²)]³</p><p>[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x⁻¹y¹)/(z²)]⁻² · [(x³z⁻¹)/(y²)]³</p><p>[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x²y⁻²)/(z⁻⁴)] · [(x⁹z⁻³)/(y⁶)]</p><p>[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x²y⁻²z⁴)] · [(x⁹z⁻³y⁻⁶)]</p><p>[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x²⁺⁹y⁻²⁻⁶z⁴⁻³)]</p><p>[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = x¹¹y⁻⁸z¹</p><p>[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = (x¹¹z²)/(y⁸)</p><p> </p><p>Jadi, hasil dari perpangkatan di atas adalah (x¹¹z²)/(y⁸).</p><p> </p><p>Semoga membantu ya😊</p>
Jawaban yang benar adalah (x¹¹z²)/(y⁸).
Ingat!
a⁻¹ = 1/a
(am)n = amn
(am)·(an) = am+n
(am)/(an) = am-n
Berdasarkan soal, diperoleh:
[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x⁻¹y⁻²⁻(⁻³))/(z²)]⁻² · [(x²⁻(⁻¹)z⁻³⁻(⁻²))/(y²)]³
[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x⁻¹y⁻²⁺³)/(z²)]⁻² · [(x²⁺¹z⁻³⁺²)/(y²)]³
[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x⁻¹y¹)/(z²)]⁻² · [(x³z⁻¹)/(y²)]³
[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x²y⁻²)/(z⁻⁴)] · [(x⁹z⁻³)/(y⁶)]
[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x²y⁻²z⁴)] · [(x⁹z⁻³y⁻⁶)]
[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = [(x²⁺⁹y⁻²⁻⁶z⁴⁻³)]
[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = x¹¹y⁻⁸z¹
[(x⁻¹y⁻²)/(y⁻³z²)]⁻² [(x²z⁻³)/(x⁻¹y²z⁻²)]³ = (x¹¹z²)/(y⁸)
Jadi, hasil dari perpangkatan di atas adalah (x¹¹z²)/(y⁸).
Semoga membantu ya😊
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