Halo kaa mohon bantuannya yaa

<p><strong>Jawabannya adalah 9 + log 2.</strong></p><p>&nbsp;</p><p>Campuran basa lemah dengan garam membentuk penyangga BASA. Selain itu penyangga basa juga dapat dibentuk apabila basa lemah bersisa dan asam kuat habis bereaksi.</p><p>&nbsp;</p><p>Perhitungan pH larutan penyangga BASA.</p><p><strong>[OH-] = Kb. mol basa lemah/mol garam&nbsp;</strong></p><p><strong>pOH = -log [OH-]&nbsp;</strong></p><p><strong>pH = 14 - pOH</strong></p><p>&nbsp;</p><p>mol HCl = 100 mL x 0,1 M = 10 mmol</p><p>mol NHO4 = 150 mL x 0,2 M = 30 mmol&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;HCl + NH4OH &nbsp;→ NH4Cl + H2O</p><p>M &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;10 &nbsp; &nbsp; &nbsp; &nbsp;30</p><p>R &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;-10 &nbsp; &nbsp; &nbsp;-10 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; +10</p><p>S &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 0 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 20 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 10&nbsp;</p><p>&nbsp;</p><p>[OH-] = 10^-5. (20 mmol/10 mmol.1)</p><p>[OH-] = 2 x 10^-5M</p><p>pOH = -log [OH-]&nbsp;</p><p>pOH = -log 2 x 10^-5</p><p>pOH = 5 - log 2</p><p>pH = 14 - pOH</p><p>pH = 14 - ( 5 - log 2)</p><p>pH = 9 + log 2</p><p>&nbsp;</p><p>Jadi,pH campurannya adalah 9 + log 2.</p>