gambar grafik

<p>Jawabannya adalah ....</p><p>f(x) = x² + x - 6</p><p>a = 1, b = 1 dan c = &nbsp;-6</p><p>&nbsp;</p><p>a. <strong>Mencari titik potong sumbu x</strong></p><p>&nbsp; &nbsp; &nbsp;Memotong sumbu x berarti y = 0</p><p>&nbsp; &nbsp; &nbsp;x² + x - 6 = 0</p><p>&nbsp; &nbsp; &nbsp;(x + 3)(x - 2) = 0</p><p>&nbsp; &nbsp; &nbsp;x = -3 atau x = 2</p><p>&nbsp; &nbsp; &nbsp;Jadi memotong sumbu x di dua titik yaitu (-3,0) dan (2,0)</p><p>&nbsp;</p><p>b. <strong>Mencari sumbu simetri</strong></p><p>&nbsp; &nbsp; &nbsp;x_p = -b/2a</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = -1/2(1)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = -1/2</p><p>&nbsp;</p><p>c. <strong>Menentukan Nilai ekstrim (nilai optimum) (y_p)</strong></p><p><strong>&nbsp; &nbsp;&nbsp;</strong> y_p = (b² - 4ac)/-4a</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= (1² - 4(1)(-6))/-4(1)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= (1 + 24)/-4</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 25/-4</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= -25/4</p><p>&nbsp;</p><p>d. <strong>Koordinat titik puncak dan jenisnya</strong></p><p>&nbsp; &nbsp; &nbsp;Koordinat titik puncak = (x_p,y_p)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= (-1/2, -25/4)</p><p>&nbsp; &nbsp; &nbsp; Grafik menhadap ke atas jadi titik puncaknya merupakan&nbsp;</p><p>&nbsp; &nbsp; &nbsp; titik balik minimum</p><p>_{&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;}</p><p>&nbsp; &nbsp; &nbsp;e. Grafiknya ada dibawah :</p><p>&nbsp;</p>