Diketahui luas segitiga PQR adalah 12√3 cm pangkat 2 Jika panjang PR=6cm PQ= 8cm, maka tentukan panjang sisi QR

<p>penjelasan dan langkah pengerjaan ada di bawah teks ini!!!</p><p>Diketahui L∆=12√3cm²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; PR=6 cm</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; PQ=8 cm</p><p>Ditanya QR=????</p><p>Jawab. &nbsp; &nbsp; &nbsp; = L∆ = ½ x PR x QR</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;12√3 =½ × PR × QR</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;QR &nbsp; = (2 × 12√3)/PR</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;QR = (2 x 12√3) / 6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<strong>QR &nbsp;= 4√3 cm</strong></p><p><strong>Kesimpulan:</strong></p><p>Jadi panjang sisi QR adalah <strong>4√3 cm</strong></p><p><strong>#Semoga penjelasan ini membantu!</strong></p>