Diberikan f(x) = x² dan g(x) = 3x + 1. Tentukan:
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Question

Diberikan f(x) = x² dan g(x) = 3x + 1. Tentukan: 
c. (f ∘ g)(-2)

Maida A · Accepted Answer

f(x)        = x²
g(x)       = 3x+1
f(g(x))  = (3x+1)²
f(g(x))  = 9x² + 6x + 1
f(g(-2)) = 9(-2)² + 6(-2) + 1
f(g(-2)) = 36 + (-12) + 1
f(g(-2)) = 25

Kevin L · Accepted Answer

I can help you with this finding (f ° g)(-2) given that f(x) = x² and g(x) = 3x + 1.
To find (f ° g)(-2), we need to perform the following steps:
 * Find g(-2). Since g(x) = 3x + 1, then g(-2) = (3)(-2) + 1 = -5.
 * Substitute -5 (which is the result of g(-2)) into f(x). Since f(x) = x², then f(-5) = (-5)².
 * Simplify the expression. f(-5) = (-5)² = 25.
Therefore, (f ° g)(-2) = 25.

Dindin D · Answer

Dari f(g(x)) = (3x+1)² langsung masukin aja -2nya jadi (-5)²=25

Diberikan f(x) = x² dan g(x) = 3x + 1. Tentukan: c. (f ∘ g)(-2)

f(x) = x² g(x) = 3x+1 f(g(x)) = (3x+1)² f(g(x)) = 9x² + 6x + 1 f(g(-2)) = 9(-2)² + 6(-2) + 1 f(g(-2)) = 36 + (-12) + 1 f(g(-2)) = 25

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