Felisa F

14 November 2023 14:57

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Felisa F

14 November 2023 14:57

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15 November 2023 02:29

<p>Jawaban yang tepat :</p><p>A. 10𝞨</p><p>&nbsp;</p><p>Yuks simak pembahasannya ...........</p><p><strong>Hambatan Paralel 1</strong></p><p>1/Rp<sub>1</sub> = 1/(R1 + R2) + 1/R3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 1/(2 + 1) + 1/6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 1/3 + 1/6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 2/6 + 1/6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 3/6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 1/2</p><p>Rp<sub>1</sub> = 2 𝞨</p><p>&nbsp;</p><p><strong>Hambatan Paralel 2</strong></p><p>1/Rp<sub>2</sub> = 1/R5 + 1/R6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 1/8 + 1/8</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 2/8</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 1/4</p><p>Rp<sub>2</sub> = 4 𝞨</p><p>&nbsp;</p><p><strong>Menentukan hambatan pengganti total</strong></p><p>R<sub>Total</sub> = Rp<sub>1</sub> + R<sub>4</sub> + Rp<sub>2</sub></p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 2 + 4 + 4</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 10𝞨</p>

Jawaban yang tepat :

A. 10𝞨

 

Yuks simak pembahasannya ...........

Hambatan Paralel 1

1/Rp1 = 1/(R1 + R2) + 1/R3

             = 1/(2 + 1) + 1/6

             = 1/3 + 1/6

             = 2/6 + 1/6

             = 3/6

             = 1/2

Rp1 = 2 𝞨

 

Hambatan Paralel 2

1/Rp2 = 1/R5 + 1/R6

             = 1/8 + 1/8

             = 2/8

             = 1/4

Rp2 = 4 𝞨

 

Menentukan hambatan pengganti total

RTotal = Rp1 + R4 + Rp2

            = 2 + 4 + 4

             = 10𝞨


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